0:17 topic
0:18 do not forget to subscribe into my
0:20 youtube channel
0:24 but updates on my lectures
0:26 for the conversion conversion from
0:37 system is the internal language
0:41 of electronic computers
0:44 so these are the steps
0:47 how to use positional notation so we
0:49 have one zero zero one one
0:55 and i may be sign two so first write
0:57 down the binary number and list the power
0:58 power
1:01 of two from left to right
1:04 so let's say we we want to convert the
1:06 binary numbers
1:09 one zero zero one one zero one one base
1:10 of two to decimal
1:13 first write it down then write down the
1:17 powers of 2 from right to left
1:22 so i start at 2 raise to 0 degrees
1:26 no raise to 0 not zero degrees raised to zero
1:27 zero
1:31 i'm reading it as one so increment
1:34 the exponent by one from each
1:37 power so it stops
1:41 stop when the amount of elements in
1:43 list is equal to the amount of digits in the
1:44 the
1:47 binary numbers or number i mean
1:50 so the example number one zero zero one one
1:50 one
1:53 zero one one has eight digits so the list
1:54 list
1:57 with eight elements would like look like this
1:58 this
2:00 one twenty eight three sixty four thirty
2:01 two six one
2:04 sixteen eight four two one four
2:08 two one so panopoulo remember [Music]
2:53 to the 6 is 64 2 to the p 32 to the
2:54 fourth 16
2:57 to the three is eight to the square root is
2:58 is
3:01 four to the one is two and two three
3:05 zero is one so yeah okay next step
3:08 write the digits of the verani number
3:09 below the the corresponding
3:11 powers of two you can get another
3:12 argument so
3:15 now just write one zero zero one one
3:17 zero one one below the
3:21 numbers so 1 28 64 32 16
3:24 8 4 and 2 and 1 so that
3:27 each binary digit corresponds with each
3:28 power of two
3:31 so the one to the right of the binary
3:32 number should
3:34 correspond with the one on the right of
3:36 the listed
3:39 powers of two and so on so you can
3:42 also write the binary digits above the
3:43 powers of two
3:46 if you prefer it that way so what is
3:47 important is that
3:51 they match up you know important
3:54 okay so for example one
3:57 zero zero one one zero one one okay
4:10 so next connect the digits in the binary
4:12 number with their corresponding powers
4:13 of two
4:15 so draw a line starting from the right
4:18 connecting each consecutive digit
4:21 of the binary number to the power of
4:24 two that is next is the least above its
4:28 begin by drawing a line from the first
4:30 digit of the binary number
4:32 to the first power of two in the fourth list
4:33 list
4:36 above it then draw a line from the
4:38 second digit of the binary number
4:42 to the second power of two in the fleece
4:45 continue connecting each digit with each
4:47 corresponding power of two this will
4:48 help you
4:51 visually see the relationship between
4:52 the two sets of
5:16 step four write down the final value of each
5:17 each
5:19 power of two so move through each digit
5:22 of the binary number if the digit is
5:24 a one write its corresponding power of
5:26 two below the line
5:28 under the line of the digit if the digit
5:30 is a zero right zero below the line
5:32 under the digit
5:35 so since one corresponds with one it becomes
5:35 becomes
5:38 a one since two corresponds with one it
5:39 becomes two
5:41 since four corresponds with zero it
5:42 becomes zero shameful any number that
5:44 multiplies zero is zero
5:46 so since a is corresponds with one it
5:47 becomes eight
5:50 since 16 corresponds with one it becomes
5:52 16 so 32 corresponds to zero it becomes zero
5:53 zero
5:56 and 64 corresponds with zero and
5:58 therefore becomes zero
6:01 while 128 corresponds with one so n
6:04 becomes one weight one way i'm getting
6:08 so remember 128 times 1 is
6:11 128. 64 times 0 is
6:15 0 32 times 0 is 0. 16 times
6:19 1 is 16 8 times 1 is 8
6:22 four times zero is zero two times one is two
6:22 two
6:25 and then one times one is one so it
6:27 takes a good
6:31 next step five add the final value so
6:31 now the
6:34 add the like the number written below
6:35 the line so here was
6:39 it to do is 128 plus 0 plus 0 plus 16 plus
6:39 plus
6:43 8 plus 0 plus 2 plus 1 is equal to 155
6:45 so this is the decimal equivalent of the
7:04 little binary number is not it
7:06 so write the answer along with b
7:07 subscript so now all
7:11 you have to do is write 150 by 10
7:14 for the decimal procedure so show that
7:17 they are working with the decimal answer
7:19 so which must be operating in powers of
7:21 10. so the more you get
7:23 used to converting from binary to
7:25 decimal the more easy
7:28 it will be you for you to memorize the
7:29 power of two
7:31 so and you'll be able to complete the
7:33 tasks more quickly
7:35 anybody remember for here yeah i think
7:36 final answer nothing
7:40 so what are 55 bits of that in subscript yeah
7:45 for example use this method to convert a
7:46 binary number
7:49 with a decimal point to decimal form
7:52 so we have 1.1 base of two so you can
7:54 use this method
7:56 when you want to convert a binary number
7:59 such as 1.2
8:02 no what one point one base of two
8:04 decimals so all you have to do is
8:06 know the number on the left side of the decimal
8:08 decimal
8:11 is in in the units position like normal
8:13 while the number of the right side of
8:15 the decimal is in the
8:17 half's position for example one times
8:19 one half percent
8:22 diva so at the end so
8:25 the one to the left of the decimal point
8:26 is equal to 2
8:29 raised to 0 or 1 because
8:32 any number that 3 is 0 is 1. so the 1 to the
8:32 the
8:35 right of the decimal is equal to 2
8:37 raised to negative 1 which is 0.5
8:41 and add up one and five
8:43 and you'll get 1.5 which is equivalent
8:45 to 1.1
8:49 in decimal notation so i'm going to n
8:52 so 1.1 so
8:56 2 is zero and so this one
8:59 super canon attend one
9:07 zero is one plus
9:10 and 2 raised to negative 1 times 1 is 0.5
9:12 0.5
9:15 so we have again at that end we have 1.5
9:18 base of 10 because of the procedure nothing
9:20 nothing
9:32 so first write down the binary numbers
9:35 so this method does not use powers as such
9:35 such
9:38 it is simpler for converting a large
9:39 number in your
9:42 head because you only need to keep track
9:43 of a subtotal
9:46 so the first thing you need to do is to
9:48 write down the binary number
9:50 you'll be converting using a doubling method
9:51 method
9:54 let's say that the number you're working
9:55 is one zero one one
9:59 zero zero one we have base two
10:02 and subscript now write down okay so
10:05 second step starting from the left
10:08 double your previous total and at the
10:10 current digit so since you're working
10:12 with the binary number one zero one one zero
10:13 zero
10:16 zero one base of two your first digit
10:19 all the way on the left is one so your
10:21 previous total is zero
10:24 so since you haven't started yet you'll
10:26 have to double the previous total
10:29 zero and add one so the current digit is zero
10:29 zero
10:32 times two plus one is equal to one so your
10:33 your
10:54 so next step so double your current
10:55 total and at
10:58 the next leftmost digit so your current
11:00 total is one now
11:02 and the new current digit is zero so double
11:03 double
11:06 one and adds
11:09 zero so one times two plus zero is equal to
11:10 to
11:39 so repeat the previous steps just keep
11:41 going next double your current total and
11:42 add one
11:45 your next uh your next digit so two
11:47 times two plus one is equal to five your
11:48 current total
12:21 so we have 11 so your new total is 11
12:48 double your current 11 and then add zero
12:49 so equals
13:04 so we have equals to 22
13:08 and 22. so next step
13:11 repeat double your current total and add
13:13 zero so we have 44
13:21 plus or times two double dot attend plus
13:25 and zero another zero it's equal to 44.
13:33 next step so continue doubling your
13:34 current and
13:36 total and adding the next digit until
13:37 you run out of the
13:40 dates so now you're down to
13:44 your last number and are almost done so
13:46 all you have to do is take your current
13:49 total with 44 and double it
13:52 along adding one so the last digit which
13:52 is what
13:56 44 times 2 plus 1 is equal to 89 you're
13:57 all done so you
14:01 convert it 1 0 0 1 0 1 1 0 0 1
14:03 base of 2 to decimal notation to its
14:18 which is equal to 89
14:22 so okay so you're
14:24 write your final answer we have to show
14:25 that you are
14:28 working with a decimal so which has a base
14:28 base
14:31 of 10. so you finally answering more
14:40 okay next i'll use this method to convert
14:41 convert
14:44 it from any base to decimal so for example
14:45 example
14:47 doubling is used because the given
14:48 number is base of two
14:51 if the given number is it of different
14:52 base replace the two
14:55 indeed method with the base of the given
14:56 number for example we
15:00 if the given number is in the base of 37
15:03 so you you replace the the times 2
15:06 with times 37 so the final result will be
15:07 be
15:09 in decimal so we have the base of 10 for example
15:10 example
15:24 times 37 plus
15:27 1 which is equal to one because it
15:30 zero times thirty seven is zero so plus
15:31 one is equal to
15:38 so one times thirty seven plus
15:42 two so we have 39.
15:49 times 37 plus
15:57 39 37 plus 3 is 1 46
16:00 so this will be your final answer with
16:01 base of