0:42 [Music]
0:45 dear students hope all you are doing
0:46 very fine
0:48 today i doctor pushpal hosh assistant
0:50 professor of doctor holy shiny goat
0:52 centre university
0:54 we'll deliver a lecture on very
0:56 important topic quantum mechanical operators
1:03 [Music]
1:04 and the
1:06 subject expert or content expert of this
1:08 topic is dr moto shimano senior
1:11 scientist ca cmc live nazar after this
1:14 lecture you will learn
1:15 that what are the quantum mechanical operators
1:18 operators
1:19 what are the eigen functions eigen values
1:20 values
1:23 what are hermitian operators
1:25 and how schrodinger equation can be formulated
1:26 formulated
1:28 as an eigenvalue problem [Music]
1:34 [Music]
1:36 now you know that quantum theory is
1:39 based on two very important constructs
1:42 operators and wave functions an operator
1:44 is a symbol that instructs
1:46 us to do is do something to whatever
1:48 follows the symbol
1:49 for example
1:51 let us consider
1:56 that d y by d x to be the d by d x
1:59 operator operating on the function y x
2:02 similarly let's take square root which
2:05 is called at sqrt
2:07 integrating operators
2:09 partial derivatives
2:10 let's say with respect to y
2:12 that is dy by dx
2:15 are other example of various kinds of operators
2:17 operators
2:18 so it is clear
2:21 that operator and operand that means the
2:24 function on which operator acts
2:29 normally an operator can be denoted
2:31 denoted
2:34 by capital letter with a current over it
2:36 which normally called a cap
2:39 thus we can write a cap f x is equal to
2:42 g x to indicate
2:44 that the operator a cap
2:47 operates on f x function to give a new
2:50 function g x
2:52 now let us take some examples for example
2:53 example
2:55 a cap 3x where
2:56 where
2:58 operator a is equal to d square by dx square
2:59 square
3:02 now performing this above operation
3:05 we can found that a cap three x
3:07 is equal to d square by d x square three
3:10 x is equal to zero
3:13 similarly we can take another example where
3:14 where
3:16 a cap is equal to d square by d x square
3:19 plus two d by d x plus 5 now when we
3:22 operate on x square
3:23 we found
3:25 that d square by d x square into x
3:30 square plus 2 d by d x into x square
3:33 plus 5 into 2 so all together
3:34 you are getting
3:37 2 plus 4 x plus 5 x square now let us understand
3:38 understand
3:41 the sum and difference of 2 operators
3:43 say a cap and e cap
3:45 by the equation known as a cap plus e
3:50 cap f x is equal to a f x plus e k f x
3:53 similarly when we subtract then it comes
3:55 like a cap minus e cap into f x is equal
3:59 to a cap f x minus e cap f x for example
4:02 if we take c cap equivalent to d by d x
4:05 then we can write c cap plus three cap
4:09 into x s cube minus five equivalent to c cap
4:10 cap
4:12 into x cube minus five
4:16 plus 3 cap into x cube minus 5 which is
4:18 equal to 3 x square plus
4:19 plus
4:21 3 x cube minus 15
4:26 so 3 x cube plus 3 x square minus 15.
4:28 now we can define the product of two
4:31 operators a cap and e cap by the equation
4:33 equation
4:36 a cap e cap f x equivalent to operator a
4:40 cap into operator e cap into f x so we
4:42 first operate on fx with the operator on
4:44 the right of the operator product and
4:46 then we take the resulting function and
4:49 operate on it with the operator on the
4:50 left of the operator product
4:52 for example
4:57 3 cap c cap f x is equal to operator 3
5:00 into c cap f x
5:03 is equal to 3 cap f prime x
5:06 is equal to 3 f prime x
5:09 for this example there is no difference
5:12 in the final result whether we first
5:14 applied one operator or the other but
5:16 not always
5:20 akp cap and ek cap have the same effect
5:21 to understand this we have to take
5:24 another example with operator c cap and
5:28 x cap where c cap is equal to d by d x
5:30 now if we write c cap
5:32 x cap f x
5:34 is equal to d by d x
5:39 x f x is equal to f x plus x f prime x
5:43 is equal to 1 cap plus x cap c cap into
5:44 f x
5:47 now if we write
5:49 x cap c cap f x
5:50 is equal to
5:54 x cap into d by d x f x
5:55 is equal to x
5:57 a prime x
6:00 thus we found that operator a cap e cap
6:02 and e cap a cap have the different
6:05 effect here a major difference between
6:06 operator algebra
6:08 and ordinary algebra
6:09 is that
6:11 numbers of the commutative law of multiplication
6:13 multiplication
6:17 but operators do not necessarily do so
6:20 now we know ae is equal to a if a and
6:22 here numbers
6:25 but operator a cap e cap and operator e
6:26 cap a cap are not necessarily equal operators
6:28 operators
6:32 now a cap e cap and e k cap are the same
6:35 then the operators a cap and operators a
6:38 are said to commute with each other
6:41 now the commutator of the two operators
6:44 a cap and e cap is defined as
6:47 a cap comma e cap is equal to
6:50 third bracket a k p cap minus e cap a f
6:53 now if a cap e k f
6:55 with the function of f x is zero
6:57 for all f x
6:59 on which the commutator acts then we
7:02 write that operator a cap and d k is
7:05 equal to zero and we say that a cap and
7:07 d cap commute with each other we have to
7:09 understand this thing very nicely
7:11 let us evaluate
7:14 the commutator of a cap e cap when a cap
7:15 is equal to
7:18 d by d x and e cap is equal to x square
7:20 now let us consider
7:22 that both these operators
7:25 act upon an arbitrary function f x
7:27 so we can write
7:30 a cap e cap f x is equal to d by d x x
7:31 square f x
7:33 now on upon differentiation we can find
7:36 2 into f x plus x square into d by d x
7:39 now e k p f f x is equal to
7:42 x square into d by d x f x
7:44 by subtracting these two results we obtain
7:46 obtain
7:49 third bracket a k p cap minus e cap a f
7:53 into f x is equal to two x f x [Music]
8:00 [Music]
8:02 now i will discuss linear operator
8:04 which is very important in quantum
8:07 mechanics the operators which are used
8:09 are all linear operators and operator a
8:11 cap is said to be linear
8:14 if the following condition holds like a
8:17 cap third bracket c 1 f 1 x plus c 2 f 2
8:21 x is equal to c 1 operator a cap f 1 x
8:24 plus c 2 operator a cap f 2 x where c 1
8:25 and c
8:29 are constants and f1 and f2 are the two functions
8:31 functions
8:33 for example the two operators
8:35 differentiate and integrates
8:37 are linear linear
8:41 because if we operate d by d x on c 1 f
8:44 1 x plus c 2 f 2 x we found c 1 d f 1 by
8:48 d x plus c 2 d f 2 by d x similarly c 1
8:51 f 1 x plus c 2 f 2 x dx
8:55 is equal to c 1 f 1 x d x plus c 2 f 2 x dx
8:56 dx
8:58 on the other hand square operator which
9:00 is normally called a square s q r is
9:03 non-linear because if you operate square
9:07 on c 1 f 1 x plus c 2 f 2 x
9:09 we found c 1 square
9:11 f 1 square x plus c 2 square f 2 square
9:15 x plus 2 c 1 c 2 f 1 x f 2 x
9:18 which is not equal to c 1 f 1 square x
9:20 plus c 2 f 2 square x
9:22 hence it is proved that square is a
9:24 non-linear operator
9:26 similarly it can be proved the square root
9:28 root
9:30 which is termed as sqrt is also a
9:32 nonlinear operator
9:36 let us say a cap fx is equal to square
9:37 root of f x
9:40 now on putting we found that a cap c 1 f
9:45 1 x plus c 2 f 2 x is equal to c 1 f 1 x
9:48 plus c 2 f 2 x to the power half so
9:49 which is
9:51 essentially not is equal to
9:53 c 1 f 1 to the half x plus c 2 f 2 to
9:56 the power half x so we can say that
9:59 square root also a non-linear operator [Music]
10:06 [Music]
10:07 it sometimes happens
10:10 that function f x when operated by
10:12 operator a
10:14 produces the same function and
10:16 multiplied by constant a
10:19 then we can write that operator a
10:22 f x is equal to small a into f x
10:24 now this equation is called an eigen
10:26 value equation which is very important
10:28 in quantum mechanics the function is
10:30 said to be an eigen function of the operator
10:32 operator
10:35 a cap and small a is called a
10:38 corresponding eigen value
10:39 eigen is a german word
10:42 meaning characteristics
10:43 eigen value
10:45 is a hybrid word basically
10:46 basically
10:48 it means
10:50 or this meaning may be characterized weird
10:52 weird
10:54 now let us solve a very simple problem
10:58 problem is that we have to show that e
10:59 to the power alpha x
11:02 is an eigen function of the operator
11:05 d n by d x that means differentiate with
11:07 respect to x
11:08 for n times
11:11 now question is what is the eigen value
11:14 we have to calculate it
11:17 now if we differentiate
11:19 e to the power alpha x n times and
11:22 obtain d n by d x e to the power alpha x
11:24 is equal to alpha to the power n e to
11:27 the alpha x and so we can say the eigen
11:30 value is alpha to the power n
11:32 now the operators can be imaginary or
11:34 complex quantities
11:36 we can see that the x component of the
11:39 momentum can be represented in quantum
11:42 mechanics by an operator of the form
11:44 operator p x
11:47 which is equal to minus i h cross del by dx
11:48 dx
11:51 now again we can solve another problem
11:53 the problem is we have to show that e to
11:56 the power i k x is an eigen function of
11:58 the momentum operator where
12:01 operator p x is equal to minus i h cross
12:04 del by dx
12:06 also we have to find the eigen value
12:08 now again if we apply the momentum
12:10 operator that means
12:14 operator p x to e to the power i k x and find
12:15 find
12:17 operator p x e to the i k x is equal to
12:21 minus i h cross del by d x e to the
12:23 power i k x
12:26 which is equal to h cross k into e to
12:27 the power i k x
12:31 so we can see that e to the i k x
12:32 is an eigen function
12:35 and h cross k is an eigen value
12:38 for the momentum operator now
12:39 now
12:42 as a home tax you can check whether the
12:44 following eigen value equation or not
12:46 that means which i am writing here
12:47 whether these are following the
12:50 eigenvaluation or not number a number
12:53 one is d by dx e to the y kx number two
12:56 you can solve whether h cross by two h
12:58 by two pi i del by d x into e to the
13:00 power i k x
13:02 a third problem you can solve it del
13:10 [Music]
13:12 now i will explain
13:14 another very important topic with
13:16 hermitian operator
13:18 in quantum mechanics the wave functions
13:20 which are allowed are always chosen from
13:23 the class of functions which are single
13:25 valued and continuous
13:27 only exception is that except at a
13:28 finite number of points where the
13:31 function may become infinite
13:33 so in the complete range of variables
13:35 you can get the value of psi and which
13:37 give a finite result
13:40 when the squares of the
13:43 of their absolute values
13:45 are integrated
13:48 over a complete range of variables
13:50 variables
13:51 so this is
13:53 very common functions of the
13:55 wave functions
13:58 now we are considering psi and phi are
14:01 two functions of the above class
14:04 now if operator a
14:05 can be such that
14:07 that integration over space
14:10 phi star a cap psi e tau is equal to
14:12 space integration
14:15 psi a cap star phi star theta
14:17 then the operator a cap is said to be an
14:20 hermitian operator that means if
14:22 any operator following the above
14:23 condition which i have just said we can
14:26 call it as a hermitian operator
14:27 now it can be proved
14:29 that eigen values of the hermitian
14:30 operator are real this is also very important
14:31 important
14:33 now the question is how we can prove it
14:36 now let us take eigen function of the
14:38 hermitian operator a cap
14:41 with the eigen value a small a
14:44 now we can write that small a f is equal
14:47 to small a cap psi is equal to s i which
14:49 you can give equation number one now
14:51 taking the complex conjugate of it we
14:52 can found
14:56 a cap star psi star is equal to a star
14:58 psi star which is equation two now
15:00 multiplying left of equation one by psi
15:03 star and integrating over space we can
15:07 get psi star a cap psi d tau is equal to
15:11 small a into psi star psi d tau which is
15:13 labeled as equation three
15:16 now by multiplying left of equation two
15:19 by psi and integrating over space we can
15:22 get integration psi a cap star psi star
15:25 d tau is equal to e star integration
15:27 sister psi theta which is labeled at
15:30 equation four now as we learnt
15:32 already that if the operator is hermitian
15:33 hermitian
15:35 then we can equate this equation three
15:37 and four
15:38 okay so the left hand side of the
15:40 equation 3
15:43 and 4 will be equal so we can write that
15:46 psi star integration psi star psi d tau
15:47 is equal to
15:50 ester into psi star psi d tau
15:54 so we can write that a minus ester
15:56 into integration psi star psi data is
15:58 equal to zero now
15:59 now
16:02 sister side theta
16:04 will be
16:06 not equal to zero so we can write a
16:09 minus ester is equal to 0 so a is equal to
16:10 to ester
16:11 ester
16:15 that means that we can say or it can be
16:17 said that the eigenvalues of hermitian
16:25 [Music]
16:28 now i will explain one very important topic
16:29 topic
16:31 of the schrodinger education so far
16:34 i have taught you about the spectroscopy
16:37 and now my subject is to connect between
16:39 the quantum mechanics which can be done
16:41 by solving that equation which is
16:43 equation for the wave function of a
16:46 particle this equation can be regarded
16:48 as fundamental axiom of quantum
16:51 mechanics as newton's law is fundamental
16:53 postulate of classical mechanics though
16:55 we cannot derive schrodinger equation at
16:57 this moment
16:59 but definitely we can trace
17:02 schrodinger's original line of thought
17:05 we can hypothesized that if matter poses
17:07 wave like properties then there must be
17:11 some wavication that will go on them
17:13 the classical wave equation can be
17:14 written as
17:16 del square u by del x square
17:19 is equal to one by f square del square u
17:22 by del t square where u is the
17:24 displacement of the string which is
17:25 called a standing wave
17:28 and is the function of two independent
17:30 variables x and
17:33 t now the equation 5 which i just mentioned
17:34 mentioned
17:36 can be solved by the method of variable
17:38 separation technique
17:41 and u x t can be written as the product
17:44 of a function of x and harmonic or
17:47 sinusoidal function of time
17:49 now we can write
17:52 u x t is equal to psi x cos omega t
17:54 which is labeled as equation six
17:57 because psi x is the special factor of amplitude
17:58 amplitude
18:02 of the mu u x t and we shall call psi x
18:05 the special amplitude of the wave
18:08 now on substituting equation 6 into
18:09 equation 5
18:10 we can write
18:13 del square psi by d x square
18:16 plus omega square by v square psi x is
18:17 equal to zero
18:20 which is enabled as equation seven
18:23 now we can introduce the idea of d
18:24 probably microwaves which i just
18:27 mentioned two classes back into equation
18:29 seven the total energy of a particle is
18:31 a sum of kinetic energy
18:33 and potential energy
18:36 we can write e is equal to p square by
18:39 two m plus u x where u x is the
18:43 potential energy now the equation 8
18:45 which i just mentioned can be rearranged as
18:45 as
18:49 p is equal to second bracket 2m e minus
18:52 ux to the power half
18:55 now according to the debugging equation
18:58 we can write lambda is equal to h by p
19:01 so by putting p we can write h by 2 m e
19:03 minus u x to the power half which is
19:05 labeled as equation 10. now the factor
19:08 omega square by v square in equation 7
19:10 can be written in terms of lambda
19:13 because we know w is equal to 2 pi nu
19:15 and nu lambda is equal to v
19:18 so putting all together
19:19 we can write
19:22 omega square by v square is equal to 4
19:24 pi square nu square by v square
19:26 is equal to 4 pi square by lambda square
19:28 now putting the value of lambda it will
19:32 be 2 m into e minus u x divided by h
19:34 cross square now substituting into
19:36 equation 7 we can write
19:40 d square psi by d x square plus 2 m by h
19:42 square into e minus u x i x is equal to 0.
19:44 0.
19:46 now this equation is known as very
19:49 famous time independent schrodinger equation
19:51 equation
19:53 importantly this is second order
19:55 differential equation for
19:56 for
19:57 psi x
20:00 and for a particle of mass m
20:02 moving in a potential field described by
20:04 capital u x
20:08 the psi x is a measure of the amplitude
20:10 of the matter wave and is called the
20:12 stationary state wave function of the particle
20:13 particle
20:17 now the equation 11 can be rewritten as
20:20 minus h cross y 2 m into del square psi
20:23 by d x square plus capital u x plus psi
20:26 x is equal to e psi x which can be
20:28 labeled equation 12. now i will explain
20:30 very important thing that how solid equation
20:31 equation
20:32 can be
20:35 evaluated or can be formulated as eigen
20:37 value problem now the left hand equation
20:40 of the equation 12 can be formulated as
20:42 minus h cos square 2 m
20:44 into del square by d x square
20:47 plus capital u x i x
20:48 is equal to e x
20:50 now we can relate the operators in
20:53 brackets by h cap and equation 13 which
20:56 i just mentioned can written as h cap
20:58 psi is equal to e psi x which is equation
20:59 equation
21:00 now the equation 14 shows that
21:02 schrodinger equation
21:04 can be formulated as an eigen value problem
21:05 problem
21:08 and the operator h cap is called a
21:11 hamiltonian operator
21:12 the wave function
21:15 is is an eigen function and the energy
21:16 is an eigen value
21:19 of the hamiltonian operator
21:21 also this shows a correlation between
21:24 the hamiltonian operator and energy the
21:26 final form will be h cap is equal to
21:28 minus h cross by two m in del square by
21:31 d x square plus u x which is labeled as
21:34 the equation 15. [Music]
21:40 [Music]
21:42 now i can summarize my talk today so in
21:44 this module we have learned
21:46 an operator is a symbol
21:49 that instructs us to do something to
21:51 whatever follows the symbol
21:53 we have learnt about various aspects of
21:56 operator algebra like how two operators
21:58 will commute with each other conditions
22:01 of an operator for being linear operator
22:04 etcetera we have discussed eigen value
22:06 eigen function and eigen equation
22:07 equation
22:09 by taking various examples
22:12 the condition of an operator forming hermitian
22:13 hermitian
22:14 is being discussed
22:17 in addition we have proved that the
22:19 eigenvalues of an hermitian operator
22:20 are real
22:22 we have
22:24 explained the condition of an operator
22:26 for being hermitian
22:27 in addition
22:30 it is proved that the eigenvalues of
22:32 hermitian operators are real
22:33 most importantly we explained
22:36 schrodinger equation from classical web equation
22:37 equation
22:40 then we have shown that how schrodinger
22:42 equation can be formulated as an
22:45 eigenvalue problem
22:48 lastly we have shown a correlation
22:50 between the hamiltonian operator and energy
22:51 energy
22:53 thank you very much for your kind attention
22:55 attention [Music]