0:31 In today's
0:35 lecture, I'll touch upon non ideal
0:40 liquid vapor systems. The ones that do
0:43 not obey Roll's law showing both
0:44 positive and negative
0:48 deviations resulting in an interesting
0:52 feature called aotropism.
0:55 Then we'll take partially missible liquid
0:56 liquid
0:59 systems. Three good examples are there.
1:02 Phenol water system, triathile ammine
1:06 water system, nicotine water system. And
1:09 lastly, we look at immissible liquid
1:13 systems to explain one interesting
1:16 distillation process called steam
1:19 distillation. Non ideal systems. As I told
1:20 told
1:24 you this is the system which doesn't
1:26 obey R's
1:29 law. There are two types. There can be
1:31 positive deviation from R's law where
1:34 the vapor pressure will be higher than
1:37 predicted from R's law. And we can also
1:40 have systems showing negative deviation
1:42 from R's law where vapor pressure will
1:47 be lower than predicted from R's law.
1:50 see the phase diagram or rather a
1:53 pressure composition diagram. You can
1:54 immediately notice the
1:57 difference in the diagram. If you look
2:01 at the dotted line shows the expected
2:05 variation in vapor pressure if the
2:07 liquids were to behave
2:10 ideally. But it is clear that the
2:14 experimental values of vapor pressure
2:17 show positive deviation. The curve is
2:20 much above that is expected from R's
2:28 components. Now here it needs an
2:32 explanation why liquids show positive
2:35 deviation. It depends on the interaction
2:36 between the
2:38 molecules. If the interaction between
2:41 the molecules of the same type that is A
2:46 and A, if it is stronger than between A
2:50 and B, it is likely that B may not find
2:52 place in the liquid state. A tries to
2:55 push it out.
2:57 Similarly, B molecules will be liking B
3:00 molecules. Therefore, A molecules are
3:04 shunted out. Molecules are unassociable
3:07 that way. If you don't like me, I don't
3:10 like you. And that's exactly what is
3:13 observed in the case of systems which
3:18 show positive deviation. Now look at the
3:20 total pressure. The total pressure which
3:23 is the sum of the partial vapor
3:26 pressures of the two components shows a
3:29 maximum. And the example that we have
3:32 here is the mixture of carbon dulfide
3:36 and acetone which shows a vapor pressure
3:39 maximum. But the diagram in which we
3:42 plot temperature versus composition is
3:45 more useful. Here is the diagram. You
3:48 can clearly see that the two liquids
3:52 have boiling points that are much
3:55 different. A is lower boiling. That
3:58 means it has higher vapor pressure. B is
4:00 high boiling which has lower vapor
4:05 pressure and you see there is a minimum
4:07 here which is called the boiling point
4:10 minimum. So these systems are the ones
4:13 which show boiling point minima. Let us
4:17 try to explain the usefulness of these
4:20 type of diagrams. You start with a
4:24 liquid mixture with composition
4:27 corresponding to A1 and heat
4:31 it. When we reach the point A2 on the curve
4:32 curve
4:35 here which can be considered as the
4:39 boiling point curve of various mixtures.
4:42 At this point A2 the liquid mixture
4:46 starts boiling. The vapors that emerge
4:49 out has the composition given by A2
4:52 prime. And if you condense this
4:54 vapor, we get a liquid having a
5:00 composition given by A3. If we heat it,
5:03 it liberates vapors having a composition A3
5:04 A3
5:08 prime. And successively if you do this
5:10 condense the vapor to get the liquid and
5:13 again evaporate that liquid collected
5:15 ultimately we reach the composition
5:18 corresponding to the point C at which
5:22 the liquid that we have shows a sharp
5:25 boiling point. It forms a vapor having
5:29 the same composition as the liquid that
5:34 we started with. And this liquid is set
5:36 to have eiotropic
5:38 composition. What do you mean by aotropic
5:40 aotropic
5:45 mixture? Eiotropic mixture is the one
5:47 which boils without changing
5:50 composition. An example of the system
5:53 that we have here is offered by a
5:57 mixture of ethanol and water. Water has
6:02 a boiling point 100 and ethanol
6:05 78.5. You have a system a mixture of
6:08 ethanol and water which gives us a
6:12 boiling point minimum which has 95%
6:15 ethanol. Let us start with non ideal
6:18 systems. The systems which show positive
6:20 deviation from R's law. A pressure
6:24 versus composition diagram is here. You
6:28 can see both the liquids show vapor
6:31 pressures that are much more than their
6:34 ideal vapor pressures as expected from
6:36 rolls law which are shown by the dotted
6:40 line. Why both the liquids show higher
6:44 vapor pressure in the mixture than their
6:47 ideal pressures? The reason is not
6:48 difficult to
6:51 find. It has something to do with the
6:53 molecular interactions.
6:56 interaction between molecules of A and
6:58 interaction between molecules of B and
7:02 between A and B. If molecules of A like
7:06 molecules of A much more than B, then
7:09 there is a chance that B molecules try
7:12 to escape and it's vice versa.
7:14 Similarly, A molecules are not liked by
7:16 B. Therefore, they also tend to escape.
7:19 Molecules are also unassociable in a
7:21 sense. As a
7:24 consequence, if you look at the total
7:27 pressure which is shown here, which is
7:29 the sum of the partial vapor pressures
7:31 of the two
7:34 components, the curve shows a maximum.
7:37 So these are the systems where the vapor
7:40 pressure maximum can be seen. An example
7:43 that we have here is a mixture of carbon
7:46 dulfide and acetone. There are several
7:48 examples of this type.
7:52 But what really matters to us a phase
7:55 diagram which we get if you plot
7:57 temperature versus composition. You can
8:00 see the liquid with higher vapor
8:04 pressure shows lower boiling point and a
8:07 liquid with lower vapor pressure shows
8:10 higher boiling point.
8:13 So we have A and B with the differing
8:16 boiling points and the boiling point
8:20 curve of the mixture which is shown here
8:23 shows a minimum. So these are the
8:26 systems which show boiling point
8:30 minima. The upper curve
8:33 shows the composition of the vapor that
8:36 is in phase equilibrium with the liquid.
8:39 Let us try to use this
8:42 diagram. Let us start with a liquid
8:44 mixture having
8:48 composition a prime and heat it. Heating
8:50 is no problem because we have two
8:53 degrees of freedom. And when we reach
8:56 point A2 on the curve, it starts
8:59 boiling. The vapors emerge and the
9:03 vapors have a composition given by point A2
9:05 A2
9:09 prime. And if we condense this vapor, we
9:12 get a liquid having a composition given
9:15 by the point A3 which is different from
9:18 that of the original composition which
9:23 has rich become richer in the liquid A
9:25 in this case which is having lower
9:27 boiling point.
9:30 And if you take this liquid and heat it,
9:34 you get a vapor having composition A3
9:36 prime. And successively if you condense
9:39 it and then vaporize it, condense it,
9:42 vaporize it, we end up with the liquid
9:43 having a composition corresponding to
9:47 point C. It's interesting here. If you
9:49 heat this liquid mixture, it will boil
9:51 at a constant temperature without change
9:54 in composition. All other compositions
9:56 will lead to a difference in the
9:59 composition of the vapor except this
10:02 point. Therefore, this point C is
10:05 interesting. It is called the aotropic
10:08 composition. What is meant by eiotropic
10:12 composition? We look at slightly later.
10:14 An example of this type of system is
10:18 offered by ethanol water. It gives us an
10:21 esotropic mixture having the composition
10:25 95% of ethanol which is called the
10:27 rectified spirit. There are systems
10:29 which show negative deviation from
10:32 Raul's law and a consequence is very
10:34 clear here. You can see the vapor
10:37 pressure is lower than expected from
10:40 Raul's law and the total vapor pressure
10:43 shows a minimum which is much less than
10:46 the ideal vapor pressure expected for
10:50 the liquid system. An example that we
10:53 have here is mixture of tricloromthane
10:55 and acetone.
10:58 Let us look at the diagram in which we
11:00 have plotted temperature versus
11:03 composition as in the earlier case. It
11:06 shows a boiling point
11:09 maximum and similar point C which is the
11:13 esotropic composition where the liquid
11:17 shows a constant boiling point which is
11:20 therefore called constant boiling
11:23 mixture and there is no change in the
11:25 composition. The rest of the discussions
11:28 are very similar. If you heat a liquid
11:30 of composition
11:34 A1, it starts boiling at A2 to give a
11:37 vapor having a composition given by A2
11:39 prime. If you remove this vapor, the
11:42 liquid composition starts drifting
11:44 towards A3 and ultimately reaches the
11:50 point C and further separation of the
11:52 two liquids is not possible. So it is
11:54 possible for us to separate the two
11:58 liquids till we reach point C the
12:02 esotropic composition. So one of the
12:04 usefulness of the diagrams is to find
12:07 out conditions where the two liquids can
12:09 be separated in what is called
12:12 distillation. But here we end up always
12:14 with anotropic mixture whether the
12:17 system shows a maximum in the boiling
12:20 point or a minimum in the boiling point.
12:23 So that needs explanation. These
12:25 mixtures as I told you are called
12:28 esotropic mixtures. Let us look at an
12:31 example of a system which shows boiling
12:34 point maximum. That means shows an esotropic
12:35 esotropic
12:37 mixture. This is offered
12:41 by nitric acid. Nitric acid forms an
12:44 isotropic mixture with water having 68%
12:47 nitric acid. You can see there is a
12:49 boiling point maximum. The temperature is
12:51 is
12:54 120.5° which is more than the boiling
12:57 point of nitric acid and
13:00 water. Let us now try to explain what is
13:02 meant by
13:04 esotropic. As we have
13:07 seen a mixture of this composition boils
13:09 without change in
13:12 composition. Our attempt to separate the
13:15 mixture by distillation fails.
13:18 entire phase diagram has this point
13:21 where the distillation is not possible.
13:23 All other mixtures can be distilled in
13:27 order to improve the purity
13:30 levels. We have an example here which is
13:33 like nitric acid. A mixture of HCl water
13:37 also gives anotropic mixture having 80%
13:41 water with boiling point of
13:44 108.6° centigrade. There are systems
13:46 showing boiling point maximum. One is
13:49 trricchloromthane acetone mixture. The
13:51 other is nitric acid water mixture and
13:54 as I told you there are systems showing
13:57 boiling point maximum. Ethanol water is
13:58 one example that we have seen. Another
14:01 is offered by dioxane water
14:04 system. Why isotropic mixtures boil at constant
14:05 constant
14:09 temperature? We can look for an answer
14:12 in the phase rule. We use the equation F
14:16 is equal to C minus P + 2. In this case,
14:18 it's a two component system. That's why
14:22 C is equal to 2. Number of phases is
14:26 two. And hence the number of degrees of
14:28 freedom available to us is
14:30 two. But during the experiment, we have
14:33 kept pressure constant at one
14:35 atmosphere. We lose one degree of
14:38 freedom. So we have only one degree of
14:40 freedom available to us. But there is a
14:42 restriction imposed on the
14:45 system. What is that restriction? At point
14:46 point
14:50 C, you can see here where the two curves
14:53 meet, the vaporous curve and the
14:55 liquidous curve meet. What does that
14:58 mean? The composition of the
15:01 vapor and the composition of the liquid
15:04 are the same. And this
15:07 restriction takes away the last degree
15:11 of freedom that we have. That means the
15:12 system becomes
15:15 invariant. The mixture therefore has to
15:19 boil at constant temperature without
15:22 change in composition. Phase rule has
15:25 answer to this problem. But then the
15:28 question arises how to remove esotropism
15:30 because such a mixture cannot be
15:33 subjected to distillation to separate
15:34 the two
15:37 components. We can try various methods.
15:40 One of them is freezing the mixture so
15:42 that one of the components present in
15:46 the mixture may freeze and hence can be
15:48 separated. We can resort to selective
15:51 absorption. Put a good absorbent which
15:54 selectively takes away by absorption one
15:57 of the components especially we try for
16:00 minor component that is present in the
16:02 mixture or by chemical
16:05 reaction add some reagent which can
16:08 react with it so that it can be
16:11 eliminated or we resort to extraction of
16:13 the minor component if you have a
16:15 suitable solvent extraction
16:18 procedure but we have heard of absolute alcohol
16:19 alcohol
16:21 In the lamps you might have seen there
16:24 are two bottles on one which is written
16:27 alcohol and on the other absolute
16:29 alcohol. What is the
16:32 difference? Difference is here alcohol
16:34 and water form an esotropic mixture containing
16:36 containing 95.6%
16:37 95.6%
16:40 alcohol which we generally call
16:42 rectified spirit. Some water can be
16:44 removed from this by chemical reaction
16:47 with the quick lime and magnesium ribbon
16:51 but about 1% water still remains in it.
16:54 It's very difficult to remove water from
16:56 alcohol because of the presence of
16:59 aotrophism in the system. Then how do
17:01 you prepare absolute alcohol which is
17:05 nothing but 100% alcohol? Let us try a
17:10 method. We use esotropism to kill
17:12 esotropism. To the esotropic mixture containing
17:14 containing
17:17 95.6% alcohol. You add a calculated
17:20 amount of benzene and distill the
17:21 mixture. What
17:24 happens? Benzene has a tendency to form
17:28 an esotropic mixture with alcohol and
17:31 water. That means a turnary esotropic
17:33 mixture is formed which distills off very
17:34 very
17:37 easily. Entire water is taken
17:40 out and what is
17:43 left alcohol and a small amount of
17:45 benzene which is deliberately added in
17:48 excess in order to ensure that all the
17:52 water is removed. On further heating
17:55 this binary esotropic mixture starts
18:00 boiling and a binary esotropic mixture
18:03 of alcohol and benzin distills off
18:06 taking away all the benzene leaving
18:10 behind 100% alcohol that is our absolute
18:13 alcohol. one of the best examples where
18:17 we can use eotropism to remove eotropism
18:20 and prepare absolute alcohol. Let us
18:22 move on to partially missible
18:24 liquids. We have several examples of
18:27 partially missible
18:30 liquids. We have dealt with completely
18:33 missible liquids in our la last episode
18:37 where we discuss solid vapor equilibria
18:40 the systems that obey Roll's law. In
18:43 this part, we'll take up partially
18:46 missible liquids like phenol water
18:50 system. Let us look at phenol water
18:52 system. The phase diagram is
18:55 here. A very simple. You have a
18:57 dome-shaped region in which the system
19:00 breaks into two phases and outside this
19:03 there is complete missibility. Phenol
19:06 and water are partially missible.
19:09 Therefore, if you take
19:12 water at any temperature, say
19:16 T1, and add phenol slowly with
19:20 stirring, phenol dissolves initially,
19:22 but when the solubility limit is reached
19:25 here on the dome-shaped curve here, the
19:27 system splits into two
19:30 phases. One with this composition, the
19:33 other with this composition. As you
19:37 continue to add additional phenol into
19:40 it, the relative amounts of the two
19:41 phases will change
19:43 change
19:47 and finally we reach a system in which
19:50 there is large excess of phenol and
19:53 again the missisibility is attained.
19:55 Therefore, on either side of the
19:58 dome-shaped area, we have complete
20:00 missibility. But within that, the system
20:04 is always split into two
20:08 phases. You can see here if we increase the
20:09 the
20:12 temperature, the compositions of the two
20:14 phases that are in equilibrium start
20:17 coming closer together. In other words,
20:19 the length of the tie line joining the
20:21 compositions of the two phases decreases
20:25 and ultimately the length becomes zero
20:29 that is a point which is called critical
20:31 solution temperature at which the two
20:35 become missible. Above this temperature
20:39 they always form one phase. So point C
20:43 is important. It is called the critical
20:47 solution temperature. Let us apply phase
20:50 rule equation to this. The equation is
20:53 F= C minus P +
20:56 2. In the one-phase region where phenol
20:59 and water are completely
21:01 missible, C is equal to 2. Two component
21:05 system phase is 1. Therefore, we can
21:07 find out the number of degrees of
21:09 freedom which is
21:12 three. As pressure is kept constant, we
21:14 are left with two degrees of freedom.
21:15 The system is
21:18 bariant. In the two-phase region where
21:20 there is partial
21:22 missisibility, number of degrees of
21:24 freedom works out to be one. The system
21:28 is univariant system. But at critical
21:31 solution temperature, that is at point
21:35 C, the two phases become identical. The
21:37 composition of the two phases become
21:40 identical. Hence the number of degrees
21:43 of freedom F becomes zero. the system
21:45 becomes invariant
21:48 system. Point C as I told you is called
21:49 critical solution temperature
21:52 abbreviated as CST. Since it is the
21:55 maximum in the curve in this particular
21:59 case it is called upper CST. It is a
22:02 characteristic of the system. It needs
22:05 some explanation here. Where do we use this?
22:07 this?
22:10 The domestic disinfectant that we get
22:12 what we call generally
22:16 phenile is a system like this. It's a
22:19 dark liquid but
22:23 clear. If you add water to it, it becomes
22:25 becomes
22:28 milky. So why it turns milky? We take
22:32 into account the effect of chemicals or
22:36 impurities on CST. CST may be made to
22:38 increase or decrease with the addition
22:41 of certain impurities deliberately. In
22:44 this particular case, you add a
22:46 substance which suppresses the CST of
22:50 phenol water system so that when you add
22:54 water, it goes into the two-phase region
22:56 from the one-phase region when it was
22:58 supplied to you.
23:01 Let us see the changes that are taking
23:04 place when we deal with such phase
23:07 diagrams. You start with the phenol
23:09 water mixture with this
23:12 composition. As you heat it and say take
23:14 it to temperature
23:17 T1 with this original composition, the
23:20 system is in two phases. One with the
23:23 composition A and other the phase that
23:27 is in equilibrium is with composition B.
23:30 And as you heat it, say to temperature
23:33 T2, the composition now of the two
23:38 phases is A prime and B prime. And the
23:40 relative amounts of the two phases are
23:42 given by the T line. The two arms of the
23:45 T line. And you can see one of the arms
23:48 start decreasing in length. And as you
23:50 increase the temperature, ultimately we
23:53 reach the point AP prime here. And you
23:56 can see that the amount of one of the
24:00 phases in this particular case BP prime
24:03 decreases almost to zero and further
24:06 increase in temperature makes the two
24:09 liquids completely missible. So we
24:12 attain missibility from a two-phase
24:15 system by heating and the missisibility
24:17 is attained by the disappearance of one
24:21 of the phases. If you start with phenol rich
24:23 rich
24:27 phase, you will have systems giving rise
24:30 to missibility
24:33 where the water-rich phase
24:35 disappears. If you start with a
24:37 particular composition in this case
24:40 given by X prime and heat it you can
24:43 clearly see that the two phases remain
24:47 in equilibrium till we reach the point C
24:51 at which both the phases are present and
24:55 missibility is attained till the
24:58 last point the two phases will be
25:01 present which means misibility is
25:04 attained when the compositions of the
25:05 two phases that are present in
25:07 equilibrium become
25:11 identical and therefore this point is
25:14 very characteristic of the
25:17 system and as I told you it is called
25:20 upper critical solution temperature.
25:24 There are other systems which
25:27 show lower CST like the one that we have
25:29 here. A
25:34 system given by water and trimethile
25:38 amine exactly like phenol water
25:43 system but the CST the critical solution
25:47 temperature is at the lowest point here.
25:50 This is called lower CST.
25:53 Why missibility is attained at lower
25:56 temperature which is unusual. Generally
25:58 we know that the solubility goes on
26:00 increasing as we raise the temperature
26:02 and ultimately missibility is attained
26:04 at a particular temperature. In this
26:07 particular case the missisibility is
26:09 there at lower temperature with the
26:10 increase in temperature the
26:13 missisibility decreases.
26:16 Probably in such systems there are some
26:18 molecular interactions which are
26:21 operative at lower temperature which
26:24 become weaker as the temperature is
26:27 raised. When you have systems like these
26:31 two upper and lower CST and interesting
26:34 system we have here is the nicotine
26:38 water system which shows both lower CST
26:41 as well as upper CST. The explanation is
26:44 similar. We have complete missibility
26:48 outside this circle and within this you
26:51 have the system in which there are two
26:52 phases in
26:55 equilibrium. Let us now look
26:59 at systems involving emissible liquids.
27:01 If we take two emissible
27:05 liquids one and two depending on density
27:09 they form separate layers. Liquid one
27:10 which is denser is cut off from the
27:13 vapor phase. Therefore only the
27:17 molecules of liquid two which is lighter
27:19 will have chance to escape to the vapor
27:23 phase. This is very clear and
27:26 therefore in such systems if we bring
27:29 about agitation very strongly both the
27:33 liquids will have chance to enter the
27:36 vapor phase so that the vapor will be in
27:39 equilibrium with both the liquids and
27:41 total vapor pressure in such cases will
27:44 be the sum of the partial vapor
27:46 pressures but in the pure state that
27:52 means P is equal to PA KN plus PB KN. It
27:56 implies that such liquid mixtures will
27:58 boil at a temperature which is lower
28:01 than the boiling point of either of the
28:05 liquids. So each liquid behaves
28:08 independently and therefore contributes
28:11 to the vapor pressure as if it is a pure liquid.
28:13 liquid.
28:16 This is true irrespective of the
28:18 relative amount of each of the liquids
28:23 present in the mixture provided their
28:26 amounts are sufficient
28:29 enough so that they exist in equilibrium
28:33 with their vapor. Now boiling point of the
28:34 the
28:37 mixture. If you take water as one of the
28:39 liquids which is immissible with the
28:40 other liquid which we takes like
28:43 nitroenzine, hydroenzine etc. even
28:45 enolene for that matter. The liquid
28:47 mixture will boil at a temperature below
28:50 100° centigrade. Take for example
28:52 boiling point of pure water as we know
28:54 is 100° centiggrade and that of analine
28:58 is 184° centigrade. the mixture boils
29:02 below 100° say around 98°
29:04 centigrade. Exactly similar arguments
29:08 holds good for any other liquid mixture
29:11 whether water is present or not. So
29:14 instead of boiling with water, it is
29:17 advantageous to use
29:20 steam because it heats up the liquid
29:23 mixture as well as it brings about
29:25 agitation which is a requirement for
29:26 both the liquids to be in equilibrium
29:29 with their vapors. This is the assembly
29:32 that we use in the distillation
29:36 process. So that the liquid mixture that
29:40 is present is made to boil over by
29:43 passing steam where the steam passed at
29:46 vigorously agitates the mixture. The
29:49 vapor gets carried water as well as that
29:51 of the liquid that is immissible with
29:53 water and collected in the distillate.
29:55 The process is called the steam
29:57 distillation. Obviously because we are
30:00 using steam. Why steam distillation?
30:02 Normal distillation of such
30:06 compounds is taking place at high
30:07 temperature because these are high
30:10 boiling liquids. They may be unstable at
30:13 that temperature. Therefore, if we use
30:15 steam distillation, they can be made to
30:17 boil at much lower temperature even
30:20 below 100° centigrade in this case
30:22 because water is being used. What is the
30:24 application? Definitely it is to
30:26 separate and purify compounds of this
30:29 type which we have mentioned earlier
30:32 which are set to be steam volatile
30:35 compounds. These are generally the
30:39 natural products that are very sensitive
30:42 to heat. Some of them are steam volatile
30:43 and steam distillation can be
30:46 effectively used to extract such plant
30:50 materials like eucalyptus, citrus oils
30:51 and natural oils which are used in
30:54 perfumery from the plants. It is found
30:57 that in steam distillation the
31:00 composition of the distillate is fixed
31:02 irrespective of the relative amounts of
31:04 the liquids present in the mixture. And
31:07 to explain this we can use phase rule
31:11 equation f is equal to c minus p + 2.
31:13 And if you substitute the value of c as
31:17 2 p as 3 we get f is equal to 1. But we
31:19 already have kept pressure at constant
31:21 at 1 atmosphere which means that the
31:23 system becomes invariant. The degrees of
31:25 freedom f becomes zero.
31:27 Therefore the mixture of the two
31:30 imissible liquids will boil at constant
31:33 temperature with fixed composition of
31:35 the vapor. That means the distillate
31:37 will have a fixed composition. We can
31:40 calculate this by using the familiar
31:42 equations that we have and you are
31:44 already familiar with it. We have come
31:46 across these equations which relate the
31:48 pressure, the partial pressure, the mole
31:51 fraction in the vapor phase, the number
31:54 of moles that are present in the
31:57 system and ultimately we can
32:02 calculate and show that the ratio of the
32:05 number of moles of each of the solutes
32:09 or each of the components present in the
32:14 distillate is constant. And in fact we
32:16 can calculate the weight ratio by
32:19 substituting the values of molecular
32:23 weight in the equation. And so that w a
32:28 by wb is equal to pa 0 into m a divided
32:32 by pb0 into ma where ma and mb stands
32:34 for the molecular weight a constant
32:37 ratio as expected. This equation in fact
32:39 has been used earlier to find out the
32:42 molecular weight of compounds that are
32:45 freshly isolated. Let us summarize what
32:49 we have seen. We have seen today non
32:52 ideal systems which show positive and
32:54 negative deviation from R's
32:58 law. We saw what areottopic mixtures.
33:01 We looked at partially missible liquid
33:05 systems which show upper CST, lower CST
33:07 as well as upper and lower CST. The
33:11 examples are here. Finally, we looked at
33:13 imissible liquid systems which are
33:15 interesting because we find a process
33:18 very important in organic chemistry that
33:19 is steam
33:22 distillation. So this brings us to the
33:24 end of our discussions on phase equilibrium.
33:26 equilibrium.
33:29 What we looked at? We started with the
33:32 definitions of terms involved in phase
33:36 equilibrium. We derived the phase rule
33:39 equation. Then saw the application of
33:41 phase rule to one component
33:44 system like water, carbon
33:47 dioxide, sulfur etc.
33:49 then used our
33:52 uh knowledge for applying it to two
33:56 component systems where we saw solid liquid
33:58 liquid
34:01 equilibria, liquid vapor
34:04 equilibria, liquid gas equilibria
34:05 equilibria
34:08 involving missible
34:10 liquids, partially missible liquids and